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#Really Speedy Algorithm Connect to the network service to get the flag. The included template script may be of use. Warning: The challenge server is currently under heavy load, so is miss-judging how fast solutions are being sent. If your script is "too slow", this may be the issue. We're working to resolve it. If your script is timing out...

Really Small Algorithm This is a follow up to Really Simple Algorithm, If you dont understand RSA, reading my writeup may be helpful. Netcatting the provided server, we get the following information n: 16856848773453133972284700106290698513247482810710495301292128221477179939745886892894154208730991202269179061578939605256564902804624955611046...

Really Simple Algorithm This is a typical RSA challenge. On netcatting the server, we get p: 692978822802216497910263439691526372004023822242590405470708610553024726 902107848499618752687457377038930308135719449550272132309308464475108356502 3419193 q: 818545152008458581431308715472370387421587511434432009344550954468777476 263587958368173933...

Really Secret Algorithm Challenge description reads as follows We've received a weird message, but it's not in a format we've ever seen before. -*-*-*- BEGIN ARR ESS AYY MSG -*-*-*- 0000000000000000000000000000000 0000000000000000000000000000000 0000000000000000000000000000000 0000000000000000000000000000000 00000000...

Mysteriuos Masquerading Message We found a file that looks to be like an ssh private key... but it doesn't seem quite right. Maybe you can shed some light on it? The contents of id_rsa.txt read tbbq yhpx:) -----BEGIN OPENSSH PRIVATE KEY----- SWYgeW91IGFyZSByZWFkaW5nIHRoaXMsIHRoZW4geW91IHByb2JhYmx5IGZ pZ3VyZWQgb3V0IHRoYXQgaXQgd2Fzbid0IGFjdHVhb...

It’s as easy as access=0000 The challenge description reads Challenge instance ready at 95.216.233.106:57735. We found a strange service, it looks like you can generate an access token for the network service, but you shouldn't be able to read the flag... We think. And we are provided with server file access.py, whose contents read m Crypto...

B007l3G CRYP70 While doing a pentest of a company called MEGACORP's network, you find these numbers laying around on an FTP server: 41 36 37 27 35 38 55 30 40 47 35 34 43 35 29 32 38 37 33 45 39 30 36 27 32 35 36 52 72 54 39 42 30 30 58 27 37 44 72 47 28 46 45 41 48 39 27 27 53 64 32 58 43 23 37 44 32 37 28 50 37 19 51 53 30 41 18 45 79 46 ...

B007L36 CRYP70… 4641N After finally solving B007l3G CRYP70, we are again presented with another variant. The description reads as follows:- As you continue your pentest of MEGACORP, you make your way to an admin-only subnet of the network. There, you find yet another custom crypto implementation. You also previously found this zip file on a ...